a stone is thrown in vertically upward direction with a velocity of 5m/s . if the acceleration of the stone during its motion be 10ms-2 in the downward direction,what will be the height attained by the stone and how much time will it take to reach there?
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v = 5ms-1
v = 0
a = -10 ms-2
s = ?
t = ?
1) v = u + at
0 =5+ ( -10 )t
-5 = -10th
to = 5/10 = 0.5 sec
to = 0.5 sec
t= 0.5 sec
2) v2 - up = 2 as
( 0 )2-(5)2 = 2 (-10)×s
s = 25 /20 = 1.25t
v = 0
a = -10 ms-2
s = ?
t = ?
1) v = u + at
0 =5+ ( -10 )t
-5 = -10th
to = 5/10 = 0.5 sec
to = 0.5 sec
t= 0.5 sec
2) v2 - up = 2 as
( 0 )2-(5)2 = 2 (-10)×s
s = 25 /20 = 1.25t
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1
hope it helps
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