Question

A stone is thrown in vertically upwards direction with a velocity of 5m/s if the acceleration of stone during its motion is 10m/s'2 in the downward direction what will be the height attained by stone and how much time will it take to reach there?

Answer 1

Answer:

max height = 1.25 m

time taken = 0.5 sec

.

Explanation:

g = -10 m/s²

u = 5 m/s

v = 0

.

v² - u² = 2gh

=> 0² - 5² = 2(-10)h

=> -25 = -20h

=> h = 25/20 = 1.25 m

.

therefore,

max height attained = h = 1.25 m

.

v = u + gt

=> 0 = 5 + (-10)t

=> 10t = 5

=> t = 5/10 = 0.5 sec

.

therefore,

time taken to reach max height = t = 0.5 sec

.

Hope this helps :)