Physics, asked by bokya3586, 10 months ago

a stone is thrown released from the top of a tower of height 200 metre find the distance covered by the stone during the fifth second of its motion

Answers

Answered by hurmatshah

1

Explanation:

u+1/2a(n-1)

0+1/2×16(5-1)

32

bokya3586: which formula is this

hurmatshah: it is the formula of distance travelled in nth second

bokya3586: kk

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