Question

A stone is thrown up vertically with a velocity of 14 m/s. How high will it rise(in m)? (g = 9.8 m/s^2)

Answer 1

H =u²/2g

H = 14×14/9.8×2

H = 10 m

Answer 2

$maximum \: height \:(h) = \frac{u {}^{2} }{2g } \\ \\ where \: u \: is \: initial \: velocity \: and \: g \: is \: gravity \\ \\ given \: (u) = 14 \: \frac{m}{s} \: and \: g \: = 9.8 \frac{m}{s {}^{2} } \\ \\ - > height \: reached = \frac{14 \times 14}{2 \times 9.8} = 10m$