Question

a stone is thrown up which reaches up to 5 m and after some time its comes back to the same place . what is the distance travalled and displacement of the stone
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Answer 1

Answer:

ANSWER

The initial velocity of the stone thrown from the cliff is 5 m/s

The stone strikes the pond near the base after 4 sec.

The stone moves in upward direction initially and then after reaching a maximum height, it starts to come down and reaches the base of the cliff.

In overall motion of the stone, the net displacement in the opposite direction of the initial velocity.

S=ut−

2

1

at

2

Substitute the values in above expression:

S=(5×4)−

2

1

×10×4

2

S=20−80=−60 m

So, the height of the cliff is 60 m.

Explanation:

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Answer 2

Answer:

the distance travelled will be 10 mand the displacement will be 0because it reached to the same place

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