Question

A stone is thrown up with a speed of 0.5ms-2.How high will the stone go before it be gins to fall?

Answer 1

Answer:

For this problem we have to use the formula : v

2

−u

2

=2aS

Here, v=0, at highest point the velocity of stone is zero and

a=g=9.8,u=10m/s and S=h

Thus, 0

2

−10

2

=2(9.8)h or h=5.1m