A stone is thrown up with a velocity of 9.8 m/s, then how much time will take to come back
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Answered by
26
final velocity = 0
intial velocity =9.8 m/s
acceleration= - 9.8 m/s ( gravity)
time =?
v=u+at
0 = 9.8 - 9.8t
- 9.8 = - 9.8t
1sec = t
intial velocity =9.8 m/s
acceleration= - 9.8 m/s ( gravity)
time =?
v=u+at
0 = 9.8 - 9.8t
- 9.8 = - 9.8t
1sec = t
Answered by
7
it's not came back.because in 9.8 m/s velocity it's went from Earth
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