Question

A stone is thrown up with a velocity such that it reaches a maximum height of 30m. If it is at a height of 10m first at time T1 and then at T2. Find the ratio of T1/T2.​

Answer 1

Let u be the initial velocity and h be the maximum height attained by the stone.

v12=u2−2gh,

(10)2=u2−2×10×2h

100=u2−10h ....(i)

Again at height h,

v22=u2−2gh

(0)2=u2−2×10×h

u2=20h  ... (ii)

So, from Eqs. (i) and (ii) we have

100=10h

h=10m

Explanation:

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Answer 2

Answer:

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Explanation:

ANSWER

Let u be the initial velocity and h be the maximum height attained by the stone.

v

1

2

=u

2

−2gh,

(10)

2

=u

2

−2×10×

2

h

100=u

2

−10h ....(i)

Again at height h,

v

2

2

=u

2

−2gh

(0)

2

=u

2

−2×10×h

u

2

=20h ... (ii)

So, from Eqs. (i) and (ii) we have

100=10h

h=10m