Physics, asked by abhishekperuvadath, 7 months ago

A stone is thrown up with a velocity which makes an angle theta with the horizontal. After 't' second what will be the magnitude and direction of the resultant velocity?​

Answers

Answered by parul291105
0

ANSWER

a) Magnitude of components

Horizontal component =Ucosθ

vertical component =Usinθ

b) Change with time

i) Ucosθ remains the same.

ii) Usinθ first decreases, becomes zero at highest point A, after which it again increases, till the projectile hits the ground.

c) We have,

vertical motion

U

V

=Usinθ

a

V

=−g

S

V

=H

V

V

=U

V

+a

V

t

⇒V

V

=Usinθ−gt

Horizontal motion

U

H

=Ucosθ

a

H

=0

S

H

=R

V

H

=U

H

+a

H

t

⇒V

H

=Ucosθ

Resultant velocity

V=

V

H

2

+V

V

2

=

(Ucosθ)

2

+(U]sinθ−gt)

2

=

U

2

cos

2

θ+u

2

sin

2

θ+g

2

t

2

−2usinθgt

=

u

2

+g

2

t

2

−2vsinθgt

As sin

2

θ+cos

2

θ=1

V=

U

2

+g

2

t

2

−2Ugtsinθ

solution

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