A stone is thrown up with an initial velocity of 50 m/s.Because of the earth's gravity the stone accelerates at the rate of -10m/s²(a) Find The maximum height reached by the stone (b) How Long does the stone remain in air
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Step-by-step explanation:
u= 50
v=0
a=g= -10
s=?
v^2 - u^2 = 2as
0 - 50^2 = 2X(-10) s
S=125
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Answer:
sahil king I don't no answer please sorry I am INT Academy English School
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