Question

A stone is thrown upward and it goes to the height to 50 m and comes down .

Calculate (i) Net displacement (ii) Net distance .​

Answer 1

Explanation:

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v

2

−u

2

=2gs

0−40

2

=−2×10×s

s=

20

160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same

Answer 2

Answer:

displacement=0 as initial and final positions are the same

distance=2x50m=100m

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