A stone is thrown upward and it goes to the height to 50 m and comes down .
Calculate (i) Net displacement (ii) Net distance .
Answers
Answered by
1
Explanation:
Initial Velocity u=40
Fianl velocity v=0
Height, s=?
By third equation of motion
v
2
−u
2
=2gs
0−40
2
=−2×10×s
s=
20
160
⇒s=80m/s
Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m
Total Diaplacement =0, Since the initial and final point is same
Answered by
0
Answer:
displacement=0 as initial and final positions are the same
distance=2x50m=100m
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