Question

a stone is thrown upward from the top of the building of height 200 with initial speed 30 metre per second after what time and hide it reaches the top of from the ground after 4 and 5 second find the distance covered by the body after what time the stone reaches ground after throwing what is the speed by which stone Striker on the ground what is the displacement and the distance by touching the ground.

Answer 1

Answer:

Here You Go

Explanation:

Height  = 200m

Initial speed = 30m/s

time taken =  5s

distance covered by the body = 200*2 = 400m

time taken by the stone to reach the ground = 5*2=10s

speed of the stone while striking the ground = 30m/s + gravitational acceleration = 30 + 9.8 =39.8m/s

displacement of the stone = 0m { because the stone gets back to its original position}

and

the total distance travelled is = same as given above 200*2=400m

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