Question

A stone is thrown upward vertically with initial
velocity 5 m/s. it will stop at height​

Answer 1

Answer:

u=0m/s g= -10m/s^2 v=5m/s

h=?

Step-by-step explanation:

using 3rd eq of motion

v^2 - u^2 = 2gh

h=1.22m

Answer 2

Answer:

Initial velocity is 5m/s

And we have to calculate maximum height

Here are two ways and a short trick to solve this.

The short trick is direct formula for maximum height i.e H = U^2/2g

i.e H = 5×5 = 25÷20

2×10

Maximum height is 1.25 m

Step-by-step explanation:

Other way around if you use 3rd equation of motion.

v^2 - u^2 = 2as

S = Maximum height

u = Initial velocity

v = Final velocity

a = Acceleration due to gravity

Final velocity is 0 since at highest point velocity becomes 0 so s will be the same formula that is given above so it's your wish either learn it directly or derive it.

I hope it will help you in your work.

Thank you ♥