Question

A stone is thrown upward vertically with initial
velocity 5 m/s. It will stop at height
(g = 10 m/s)

​

Answer 1

Answer:

It will stop at height = 1.25 meter

Step by Step Explanation:

Given that,

A stone is thrown upward vertically with initial velocity 5 m/s

Here,

Initial velocity of the body = 5 m/s

let the maximum height that the ball can attain be h

now at its maximum height body will at rest

so,

its final velocity will zero

now we have,

Initial velocity(u) = 5 m/s

final velocity(v) = 0 m/s

gravitational acceleration(g) = -10 m/s

[acceleration against the gravitational force]

now,

by the gravitational equation of motion,

v² = u² + 2gh

putting the values,

0 = 5² + 2(-10)h

-20h + 25 = 0

-20h = -25

h = 25/20

h = 1.25 m

so,

It will stop at height = 1.25 meter

_______________

NOTE :

Formulas:

For upward movement

time to reach maximum height(t)

t = u/g

time to reach its initial position (T)

T = 2u/g

For downward movement

speed of body in hitting ground(v)

v = u²/2g

Height (H)

H = ½gt²

Answer 2

Answer:

given :-

velocity of stone = 5m/s

we will consider negative acceleration as good =-10 m/s

height would be maximum when v =0

then :-

v^2 = u^2 +2as

5^2 = 0+ 2×10×s

25=20s

s= 4/5

therefore maximum height is 4/5 m

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