Question

a stone is thrown upward. when particle is at a height half of its maximum height its speed is 10m/s then the maximum height attained by the particle is

Answer 1

let intitial velocity is U and maximum hight is h

so at maximum hight velocity will be zero

0 =U2 -2gh

U2 =2gh ..........1

now given velocity is = 10m/sec at hight h/2

so 102 = U2 -2gh/2

     100 =2gh -gh

    h = 100/10

   h =10 m