Question

a stone is thrown upward with a speed of 25m/s . another stone is simultaneously thrown downward form the same point with speed 10m/s. the relative velocity of 1st stone with respect to 2nd stone is (consider both stones are in air)

Answer 1

Answer:

V1V2 = V1 - V2

= 25 - 10

= 15

Explanation:

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Answer 2

Answer:

The relative velocity of 1st stone with respect to 2nd stone will be equal to 35m/s.

Explanation:

As given in the question:

The first stone is thrown upward with speed $=25ms^{-1}$

The second stone is thrown downward with speed $=-10ms^{-1}$

When both stones are in the air, they fall under the gravity. Therefore their relative acceleration is zero. Relative velocity will be constant.

The relative velocity of 1st stone w.r.t. 2nd stone $= v_{12}=v_{1}-v_{2}$

  ∴        $v_{rel}=25-(-10)=35ms^{-1}$

Therefore relative velocity of 1st stone w.r.t. 2nd stone is equal to 35m/s in the upward direction.