Question

A stone is thrown upward with the velocity of 20m/s. Calculate the height attained by the object at the
half way mark?

Answer 1

Answer:

The height attained by the object at the  half way mark will be 15.3 m.

Explanation:

The initial velocity of the body, u = 20 m/s

Acceleration acting on the body, a = g = -9.8 m/s²

The final velocity of the body at maximum height, v = 0 m/s

Time taken to attain maximum height, t = (v - u) / a

                                                                  = (0 - 20) / -9.8

                                                                  = 2.04 s

So time taken to reach halfway mark will be t/2 = 2.04/2 = 1.02 s

The height attained during this halfway mark can be calculated using the 2nd equation of motion.

S = ut + (at²)/2

S = (20 × 1.02) + (-9.8 × 1.02²)/2

S = 15.3 m