Question

a stone is thrown upward with velocity 10m/s from the tower of height 40 m .it moves up and then falls at the bottom of the tower. find the time taken by stone in reaching the bottom of the tower
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Answer 1

Answer:

2.04 second

Explanation:

At the highest velocity is 0.

Here, acceleration = - g(going upward) and g(coming downward.

Using eauations of motion:

• v = u + at

= > 0 = 10 + (-9.8)t

= > (-10)/(-9.8) = t

= > 10/9.8 = t

Total time = 2 * time taken to reach the highest point

= > total time = 2 * (10/9.8) = 2.04 sec