A stone is thrown upwards at a initial speed of 5m/s from a height of 1 m . How much later on must a 2nd stone be dropped from same height so that the two stones reach the ground simultaneously
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We will use kinematic equations for this question.
S = ut + 1/2gt² V² = u² + 2gs V = u + gt
In our case :
U = 5 m/s g = 10m/s² v= 0
Since it is projectile motion, it will have a negative.
0 = 5 - 10t
5 = 10t
t = 0.5 s
For the stone to come back to the same level, it will take the same time hence :
2 × 0.5 = 1 second.
It will be after 1 second that the second stone will be releases so that they reach the ground at the same time.
S = ut + 1/2gt² V² = u² + 2gs V = u + gt
In our case :
U = 5 m/s g = 10m/s² v= 0
Since it is projectile motion, it will have a negative.
0 = 5 - 10t
5 = 10t
t = 0.5 s
For the stone to come back to the same level, it will take the same time hence :
2 × 0.5 = 1 second.
It will be after 1 second that the second stone will be releases so that they reach the ground at the same time.
Answered by
0
We will use kinematic equations for this question.
S = ut + 1/2gt² V² = u² + 2gs V = u + gt
In our case :
U = 5 m/s g = 10m/s² v= 0
Since it is projectile motion, it will have a negative.
0 = 5 - 10t
5 = 10t
t = 0.5 s
For the stone to come back to the same level, it will take the same time hence :
2 × 0.5 = 1 second.
It will be after 1 second that the second stone will be releases so that they reach the ground at the same time
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