Question

a stone is thrown upwards from the ground of velocity u​

Answer 1

hєчα mαtє! ítѕ σjαѕvєє hєrє.

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Initial velocity is u and final velocity is v=3u and acceleration is g.

So height is h=(v2−u2)/2g=((3u)2−u2)/2g=(9u2−u2)/2g=4u2/g

hσpє ít hєlpѕ чσu mαtє!