Question

a stone is thrown upwards from the top of a tower 75m high reaches the ground in 6s. Find the velocity with which it is thrown upwards g=10ms -2​

Answer 1

v =0. At topmost point v=0

h= 75m

t = 6 s

g= -- 10 m/s

u= ?

v = u + at

putting values we get

0 = u + -10 ×6

u = 60 m/s

Answer 2

Answer:

Velocity at which ball was thrown

= 30 m/s

Step by step explanations :

given that,

a stone is thrown upwards from the top of a tower 75m

here,

let the initial velocity of the stone = u

also given,

the height of the tower = 75 m

and,

The time taken by the stone to reach the ground = 6 seconds

now,

now we have,

initial velocity(u) = u

time taken(t) = 6 seconds

gravitational acceleration(g) = -10 m/s²

displacement travelled(s) = 75 m

by the gravitational equation of motion,

S = ut + ½ gt²

putting the values,

75 = u(6) + ½ (-10)(6)(6)

6u = 180

u = 180/6

u = 30 m/s

so,

Velocity at which ball was thrown

= 30 m/s