A stone is thrown upwards with a speed v from the top of a tower.it reaches the ground with a velocity double the initial value.what is its acceeration?
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A stone thrown vertically upwards from the top of a tower ... an initial velocity u reaches the ground with a velocity 3u the ... Can u xplain dis detailed..with all d values.
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Final velocity = 3v
Initial velocity = v
Using v^2 - u^2 = 2as
We get s = 4u^2/g....
That's your answer..
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