Question

A Stone is thrown upwards with a velocity of 25 m/s . Find the maximum height it reached?
Please help....​

Answer 1

Answer:

2t

Explanation:

It is thrown up with 25m/s means when it reaches max height its final velocity will be 0.

v=u+at

0=25 + (-10)t

t=2.5(time required to reach max height)

Now , s=ut + 1/2 a t^2

s will be the max height it attained ( a=-g)

Total time will be 2t.

Answer 2

Explanation:

the velocity becomes zero. So, v final=0

It is given that the initial velocity, v initial=25m/s . The acceleration due to gravity is g=9.8m/s2 .This means that the velocity decreases by 9.8 m/s every second . Thus the velocity becomes zero at time, Δ t = v initial g=259.8=2.55seconds .

Also notice that, since the acceleration is constant, we can easily find the average velocity.

∴v average =v initial+v final2=25+02=12.5m/s

Since we know the average velocity during the entire journey and the time of flight, we can find the total distance travelled, or to phrase it properly, the height. Since total distance is average velocity times the time of flight, so naturally it follows that

Height=v average∗Δ t=12.5∗259.8=31.89m■