Question

A stone is thrown upwards with a velocity of 8.00m/s from a window that is 5.2 m above the ground
a) calculate the maximum height reached by the stone
b)calculate the velocity the stone will hit the ground at

Answer 1

Answer:

a) 3.2m,

b)

$2 \sqrt{42} m \div s$

Explanation:

a) u=8m/s, v=om/s, g=10m/s2

V2=u2-2gs

(0)2 =(8)2-20s

0-64 =(-20s)

64/20=s

3.2m=s.