A stone is thrown upwards with an initial velocity v The distance travelled in time
v/g
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Answer:
1/2 (v^2)/g
Explanation:
S=ut+1/2gt^2
S=v×v/g + 1/2(-g)(v/g)^2
S=v^2/g - 1/2 v^2/g
S= 1/2 v^2/g
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