Question

a stone is thrown upwards with velocity v . at half the height its velocity will be

Answer 1

height it's velocity will be
solution

Answer 2

Answer:

( v/ root2)

Explanation:

Total height it traversed =>

0^2 = v^2 – 2gH

H = v^2/2g...............................(1)

At half the height.

v’^2 = v^2 – 2g(H/2)

v’^2 = v^2 – v^2/2 = > v^/2 {from eqn. (1)}

v’ = v/root(2) m/s