a stone is thrown vertically downward with a speed of 2m/s from the top of the tower of height 40m. then what is the velocity of stone after 1 second.
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Answer:
Velocity after 1 second = 11.8 m/s.
Explanation:
u = 2m/s
a = acceleration due to gravity = 9.8 m/s^2
t = 1 second.
Applying the equation v = u + at
=> v = 2 + (9.8)(1)
=> v = 11.8 m/s
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