Question

a stone is thrown vertically downward with a speed of 2m/s from the top of the tower of height 40m. then what is the velocity of stone after 1 second.

Answer 1

Answer:

Velocity after 1 second = 11.8 m/s.

Explanation:

u = 2m/s

a = acceleration due to gravity = 9.8 m/s^2

t = 1 second.

Applying the equation v = u + at

=> v = 2 + (9.8)(1)

=> v = 11.8 m/s

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