a stone is thrown vertically downwards of a tall Cliff the distance as it travels in metres is given by the formula S=4t + 5t^2, where t is the time in seconds after the stone release.
a)what is the rate of change of distance with time DS / DT? (this represents the velocity)
b)how many seconds after its release is the stone travelling at a velocity of 9m/s
c)the speed of the stone as it hits the ground is 34m/s . how many seconds after its release did the stone hit the ground?
d)using your answer to part C calculate the distance the stone Falls and hence the height of the Cliff
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Answer:I am not sure if you if you if you if you if you if you if you if you
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The rate of change of displacement of an object (displacement over elapsed time) is velocity. Velocity is a vector since it has both magnitude (called speed) and direction.
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