Question

a stone is thrown vertically from a bridge with velocity 3m/s if it strikes the water under the bridge after 2s the bridge is at a height of​

Answer 1

Hii its tom85

H = ut - gt^2

H = 6 - 40

H = -34m(in opposite directions)

______/\______☺️

Hope it may helps you

Answer 2

Answer:

s= ut + 1÷2 gt^2=

=s=3×2+1÷2×10×4=

s=6+40÷2

s=6+20 =

s=26

hope it helps