Question

a stone is thrown vertically up at 20m/s from a tower of height 80m/s the speed with which it hits the ground is

Answer 1

Answer:

Step-by-step explanation:

H= (u^2/2g)

= (200/2× 10)

=20

Now it is like a free fall motion

So, V= U+at, but we don't know t

So S = ut +at^(2)/2

U =0

100 = 0.5 × 10 ×t^2

Now u get t

Substitute t in v= u+at

So you will get velocity when the body hits ground