Question

A stone is thrown vertically up from a bridge with velocity 3m/s.if its strikes the water under the bridge after 2s,the bridge is at a height of​

Answer 1

Answer:

given,

u=3m/s

v=0

t=2s

height(s)=?

acc=-10m/s^2

so, (v)^2-(u)^2=2as

0^2-3^2=2×(-10)×s

-9=-20×s

9/20=s

s=0.45m

Explanation:

so height of bridge is 0.45m .

Answer 2

Answer:

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