Physics, asked by kasim8497, 11 months ago

A stone is thrown vertically up from a bridge with velocity 3m/s.if its strikes the water under the bridge after 2s,the bridge is at a height of​

Answers

Answered by bangikarthik7
6

Answer: 14

Explanation:

U=-3 ms^-1

G=10ms^-2

T=2sec

S= (U)(T) + 1/2(A)(T)²

S= (-3)(2)+1/2(10)(2)²

S= -6+20

S= 14

Answered by kallavenkat5
0

Answer:

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