Question

A stone is thrown vertically up wards with an initial velocity of 20m/s and reach a maximum height of 20m. What is the time to reah maximum height?

Answer 1

Answer:

Its thrown vertically opposite, so at the highest point the v = 0 m/s.

And u is given as 20 m/s.

Taking a = 10 m/s2

Applying third equation of motion,

v2= u2 + 2as

0=202+2(-10)(s) {Negative sign of a shows acceleration in opposite direction}.

0=202−20(s)

400 =20(s)

20 m = s

So object will go upto 20 metres

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