Question

A stone is thrown vertically up with an initial of 10m/s . Find the maximum height reached and the time of ascent ( take gravitational force= 10m/second square)​

Answer 1

Answer:

for maximum height

here initial velocity = 10m/s

$h = \frac{ {u}^{2} }{2g}$

$h = \frac{ {10}^{2} }{2 \times 10} = \frac{100}{20} = 5m$

now we find time of ascent ,

time of ascent = usin (theta)/g

=10sin 45°/10

= 10/10

= 1s