a stone is thrown vertically up with velocity 40m/s........
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What do you want to know about a stone being thrown up with a velocity of 40m/s?
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Given,
Initial Velocity (u) = 40m/s
g = 10m/s2
Final Velocity (v) = 0m/s
2gs = v2 - u2
2*-10*s = 0*0 - 40*40
-20*s = 0 - 40*40
s = 40*40/20
s = 80m
Total distance covered by him = 2*80 = 160m
Net Displacement = 0
Initial Velocity (u) = 40m/s
g = 10m/s2
Final Velocity (v) = 0m/s
2gs = v2 - u2
2*-10*s = 0*0 - 40*40
-20*s = 0 - 40*40
s = 40*40/20
s = 80m
Total distance covered by him = 2*80 = 160m
Net Displacement = 0
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