Question

A stone is thrown vertically upward direction with the velocity of 6m/s. If the acceleration is 5m/s2, what will be the height attained by the stone?​

Answer 1

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Given, initial velocity, u$= 5 {ms}^{ - 1}$

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=$- 10 {ms}^{ - 2}$

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation,

${v}^{2} - {u}^{2}$as, we have

$s = \frac{ {v}^{2} {u}^{2} }{2a}$

$= {0}^{2} - \frac{ {5}^{2} }{2} \times ( - 10) = 1.25m$

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s