A stone is thrown vertically upward from the top of a tower with velocity u and it reaches the ground with a velocity 3u diet of tower is
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Explanation:
When it reaches maximum height and falls down till the point of projection, the velocity at that instant and projection will be same. Using that logic, we will solve it.
Firstly, we use V=U+AT to find time.
3u=u+10t, t=u/5
Substitute this time in displacement formula.
S=u(u/5)+1/2 * 10(u/5)2
s = 10u2/25
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Answer: 4u^2/g
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