Question

A stone is thrown vertically upward from the top of a tower 50m high with an initial velocity of 20m/s Calculate i. The maximum height ii. Time taken to reach the maximum height iii. Total distance it covered

Answer 1

A stone is thrown vertically upward with an initial velocity of 40m/s. Taking g=10m/s

2

, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

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VIDEO EXPLANATION

ANSWER

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v

2

−u

2

=2gs

0−40

2

=−2×10×s

s=

20

160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same

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