Question

a stone is thrown vertically upward with a height 80 m with what speed it thrown​

Answer 1

Answer:

u =28 m/s

a) When maximum height reached, velocity =0

conserving total energy,

21m×282=21m×D2+mgh

→h=2×0.8282=40 m

b) One second after u reaches maximum height t=1 sec.

V=u+at=0+9.8×1=9.8 m/s

c) No, because at maximum height, velocity is zero so 1 sec after in any case, will given velocity 9.8×1=9.8 m/s.