Question

A stone is thrown vertically upward with a speed of 10.0 metre per second from the edge of a cliff 65 metre height what will be its speed just before hitting the bottom

Answer 1

Explanation:

here is the solution.

i have calculated the distance travelled by object upwards then from that point calculated final velocity.

Answer 2

Explanation:

H=v^2-u^2/2g

65=v^2-10^2/20

1300+100=v^2

v=√1400=37.41(approx)