Question

% A stone is thrown vertically upward with a speed of
28 m/s. (a) Find the maximum height reached by the
stone. (b) Find its velocity one second before it reaches
the maximum height. (c) Does the answer of part
(b) change if the initial speed is more than 28 m/s such
as 40 m/s or 80 m/s?
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Answer 1

Answer:

hope u understand this answer

Explanation:

Initial speed=u=28m/s

Final velocity at maximum height=v= 0 m/s

a=g=10m/s2

A) maximum height attained by stone=u²/2g=28x28/2x10=39.2m

B) time=t=u/g=28/10=2.8 sec

t1=2.85-1=1.85

V=u+at

=28 -(10)(1.85)=28-18.13=9.87 m/s

Hence the velocity is 0.87 m/s

c) No it will not change .

Because after 1 sec final velocity becomes zero for any initial velocity..