Question

A stone is thrown vertically upward with a speed of 28m/s. (a) find the maximum height reached by the?

Answer 1

Hey mate ^_^

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Answer:
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Initial Speed (u) $=28m/s$

Final velocity at maximum height (v) $=0m/s$

a = g $=10m/s^2$

(a) The maximum height reached by the stone:

$\frac{u ^{2} }{2g} = \frac{28 \times 28}{2 \times 10} = 39.2m$

#Be Brainly❤️

Answer 2

Heyy mate ❤✌✌❤

Here's your Answer... .


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Initial speed = 28m/s

Final velocity = 0m/s

a= 10 m/s^2

maximum height attained by stone

=u²/2g=28x28/2x10

=39.2m
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