Question

a stone is thrown vertically upward with a speed of 40 metre per second the time interval for which particle was above 40 metre from the ground is equal to 10 metre per second square ​

Answer 1

Answer:

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Answer: The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.

Explanation:

Given that,

Final velocity v = 0

Initial velocity u = 40m/s

We know that,

Using equation of motion

v^2=u^2+2gh

0-40^2= 2\times 10\times h

The maximum height is

h = 80\ m

The stone will reach at the top and will come down

Therefore, the total distance will be

s = h_{1}+h_{2}

s = 80\ m+80\ m = 160 m

The net displacement is

D = h_{1}-h_{2}

D = 80\ m-80\ m= 0

Hence, The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.