Question

A stone is thrown vertically upward with a speed of 40m/s. The time interval for which particle was above 40 m from the ground is (g=10m/s²)

Answer 1

Answer:

Initial velocity=40m/s

Height(h)=40 m

Time(t)= ?

acceleration due to gravity(g)=10m/s²=-10m/s²(thrown upward)

By equation :

• v=u+gt

$0 = 40 + ( - 10)t$

$- 40 = - 10t$

$- 40 \div - 10 = t$

$4 = t$

so

4 seconds=time

• Therefore,the time taken is 4 seconds.

Answer 2

Answer:

Step-by-step explanation:

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