A stone is thrown vertically upward with a speed of 49m/s. Then the velocity of the stone, one second before it reaches the maximum height is
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Answer: Initial velocity (u) = 49 m/s
Let the time taken to reach the maximum height be t.
Acceleration due to gravity = - 9.8 m/s^2
Final velocity = 0 m/s
Now, using first equation of motion:
0 = 49 - 9.8 × t
t = 5 seconds
Now, we need to find the velocity just 1 second before reaching the highest point.
Hence, time = 4 seconds
Hence, the velocity just 1 second before reaching the highest point is 9.8 m/s.
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