Question

a stone is thrown vertically upward with a speed of 49m/s .then the velocity of the stone , one second before it reaches the maximum height is​

Answer 1

Answer:

Explanation:

Is it 10m/s ?

Then this is the ans

T(half)= u/g

4.9 sec

So one min earlier hence 3.9 sec

3.9=u/10

U'=39

Therefore u''= 10m/s