Question

A stone is thrown vertically upward with a speed of 5m/so. How much high the Stone goes before back to the earth acceleration =9.8m/s^2

Answer 1

Answer:

Height = 1.25mTherefore, the stone goes 1.25m high before back to the earth.

Answer 2

Answer:

Initial Velocity=5m/s

Final velocity= 0

Acceleration=-9.8m/s^2

So height will be,

2as= v^2-u^2

2*-9.8*s=0-25

-19.6s=-25

s = 25/19.6

1.27m