Question

A stone is thrown vertically upward with a speed of49 ms−1 . Then the velocity of the stone, one second before it reaches the maximum height is

what is the solution?
the answer will be 9.8 .

but, what is the solution?​

Answer 1

Answer:

9.8ms

Explanation:

Initial velocity of the stone is u=49 m/s

Acceleration: a=g=9.8 ms

−2

While ascending, the stone will deccelerate and finally its velocity will become zero at the maximum height.

Let t is the time taken by the stone to reach the maximum height.

Using the equation v=u−gt

t=

−g

v−u

=

−9.8

0−49

=5 sec

We need to find the velocity of the stone at t=5−1=4 sec

Again, Using the equation v=u−gt

v=49−(9.8×4)=49−39.2=9.8 m/s