Question

A stone is thrown vertically upward with a velocity of 30 ms", if g = 10 m/s² then
what is the distance traveled by the particle during the 1st second of its motion is:
a. 30 m
b. 25m
d. None of these
c. 10m​

Answer 1

Solution :-

Given ,

• Velocity of stone = 30 m/s
• Acceleration due to gravity = -10 m/s²
• Time = 1 s

To find ,

• Distance travelled by the particle

Now , finding distance travelled using 3rs equation of motion

s = ut + 1/2 gt²

Where

• v → Final velocity = 0 m/s
• u → initial velocity = 30 m/s
• g → Acceleration due gravity = -10m/s²
• s → distance travelled = ?
• t → time taken = 1 s

Note : Here , the final velocity will be zero because the stone goes upward and stop and come down .

Substituting the values we have

→ S = 30(1) + 1/2 × (-10) × (1)²

→ S = 30 - 5 × 1

→ S = 30 - 5

→ S = 25 m

Hence , distance travelled by the particle during the first second = 25 m.

Answer 2

OK dear..

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