a stone is thrown vertically upward with a velocity of 40 metre per second and is quarterback taking gravity is 10 M per second per second square calculate the maximum height reached by the stone
Answers
Answered by
6
given,
Initial velocity of the stone u =40m/s
g=-10 [since for gravity g is negative ]
Using V^2=U^2+2gh
where h= maximum height attained by the stone
h=-40x40 /2x-10 [V here is 0 because when it reached the maximum height it will stop and fall down ]
h=80m
Hence maximum height attained by the stone =80metres
Initial velocity of the stone u =40m/s
g=-10 [since for gravity g is negative ]
Using V^2=U^2+2gh
where h= maximum height attained by the stone
h=-40x40 /2x-10 [V here is 0 because when it reached the maximum height it will stop and fall down ]
h=80m
Hence maximum height attained by the stone =80metres
Similar questions